A marble block of mass 2 kg lying on ice when given a velocity of `6m//s` is stopped by friction in 10s. Then the coefficient of friction is

Options

A. 0.01
B. 0.02
C. 0.03
D. 0.06

Answer

D

Explanation

Retardation of the marble block because of f
`a = (mu N)/(m)=(mu m g )/(m) =mu g `
Now using V =u + at, we get,
`0 = 6 - (mu xx 10 )xx10 `
Which gives `mu = 0.06`