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Consider a car moving on a straight road...

Consider a car moving on a straight road with a speed of `100m//s`. The distance at which car can be stopped is `[mu_k=0.5]`

A

400 m

B

100 m

C

1000m

D

800m

Text Solution

Verified by Experts

The correct Answer is:
C
Retardation due to friction `= mu g`
We know `v^(2) = u^(2) +` as `:. 0 = (100)^(2) - 2 (mu g)s`
or `2 mu gs = 100 xx 100` or `s = (100 xx 100)/(2 xx 0.5 xx 10) = 100 m`
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