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A ball of mass 0.2 kg is thrown vertical...

A ball of mass 0.2 kg is thrown vertically upwards by applying a force by hand. If the hand moves 0.2 m while applying the force and the ball goes upto 2 m height further, find the magnitude of the force. (Consider `g=10m//s^2`).

A

20 N

B

22 N

C

4 N

D

16N

Text Solution

Verified by Experts

The correct Answer is:
B
From B to C, `v^(2) = u_(1)^(2) - 2 xx 10 xx 2`
`implies 0 = u_(1)^(2) - 40 implies u_(1) = sqrt(40) m//s`
Let from A to B let the acceleration be a `u_(1)^(2) = u^(2) + 2a xx 0.2 implies 40 = 0^(2) + 0.4 a`
`implie a = 100 m//s^(2)`
Now F - mg = ma
`implies F = m (g + a) = 0.2 [10 + 10] = 22 N`
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