A block of mass 'm' is connected to another block of mass 'M' by a spring (massless) of spring constant 'k' The blocks are kept on a smooth horizontal plane. Initially the blocks are at rest and the spring is unstretched Then a constant force 'F' starts acting on the block of mass 'M' to pull it. Find the force on the block of mass 'm' :

Options

A. `(mf)/(M)`
B. `((M + m)F)/(m)`
C. `(mF)/((m + M))`
D. `(MF)/((m + M))`

Answer

C

Explanation

Acceleration of system
So, force acting on mass `F = ma = (mF)/(m + M)`