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System shown in fig is in equilibrium an...

System shown in fig is in equilibrium and at rest. The spring and string are massless now the string is cut. The acceleration of mass 2m and m just after the string is cut will be:

A

g/2 upwards, g downwards

B

g upwards, g/2 downwards

C

g upwards, 2g downwards

D

2g upwards, g downwards

Text Solution

Verified by Experts

The correct Answer is:
A
For equilibrium of mass m : T = mg
Now, the string is cut. Therefore, force is decreased on mass m upwards and downwards on mass 2m. Hence, net force on m is now mg in downward direction. Hence, the acceleration of ‘m’
`:. A_(m) = (mg)/(2m) = (g)/(2)` (downwords)
For ‘2m’ block net force will be mg in upward direction. Hence, acceleration of the block ‘2m will be 2m will be
`:. a_(2m) = (mg)/(2m) = (g)/(2)` (upwards)
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