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If a man at the equator would weigh (3//...

If a man at the equator would weigh `(3//5)`th of his weight, the angular speed of the earth is

A

`sqrt(2/5 g/R)`

B

`sqrt(g/R)`

C

`sqrt(R/g)`

D

`sqrt(2/5 R/g)`

Text Solution

Verified by Experts

The correct Answer is:
A
3/5 mg = `mg-mRomega^2` , `omega^2=g-3/5g rArr omega = sqrt(2/5 g/R)`
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