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A satellite revolves in the geostationar...

A satellite revolves in the geostationary orbit but in a direction east to west. The time interval between its successive passing about a point on the equator is:

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A, B
`omega_"satellite"=omega_"earth"=(2pi)/T=((2pi)/24)` rad `h^(-1)`
Relative velocity, `omega=omega_"satellite"+omega_"earth"=2((2pi)/24)=((2pi)/12) therefore T'=(2pi)/omega` = 12 h
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