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The acceleration due to gravity on the p...

The acceleration due to gravity on the planet `A` is `9` times the acceleration due to gravity on planet `B`. A man jumps to a height of `2 m` on the surface of `A`. What is the height of jump by the same person on the planet `B` ?

A

6m

B

`(2/3)` m

C

`(2/9)` m

D

18 m

Text Solution

Verified by Experts

The correct Answer is:
D
It is given that, acceleration due to gravity on planet A is 9 times the acceleration due to gravity on planet B i.e.,
`g_A=9g_B` ….(i)
Form third equation of motion
`v^2=2gh`
At planet A, `h_A=v^2/(2gA)` …(ii)
At planet B , `h_B=v^2/(2g_B)`...(iii)
Dividing eqn. (ii) by eqn. (iii) , we have
`h_A/h_B=g_B/g_A`
From eqn. (i)` g_A=9g_B therefore h_A/h_B=g_B/(9g_B)=1/2` or `h_B=9h_A=9xx2=18`m ( `h_A` = 2m )
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