If g is acceleration due to gravity on t...

If `g` is acceleration due to gravity on the surface of the earth, having radius `R`, the height at which the acceleration due to gravity reduces to `g//2` is

A

`2.6xx10^6` m

B

`6.4xx10^6` m

C

`9.0xx10^6` m

D

`1.6xx10^6` m

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The correct Answer is:

A

`g'=g/((1+h/"Re")^2) " " 4.9=9.8/((1+h/"Re")^2) rArr (1+h/"Re") =sqrt2`=1.414
`rArr h/(Re)`=0.414 `rArr h = 0.414xxRe=0.414xx6.4xx10^6=2.6xx10^6`

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