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If the angular momentum of a planet of m...

If the angular momentum of a planet of mass m, moving around the Sun in a circular orbit is L, about the center of the Sun, its areal velocity is :

A

`L/(2m)`

B

`(4L)/m`

C

`L/m`

D

`(2L)/m`

Text Solution

Verified by Experts

The correct Answer is:
A

`dA=1/2R^2 d theta`
`(dA)/(dt)=1/2 R^2 (d theta)/(d t) =R^2/2 omega`
`L=mR^2 omega therefore (dA)/(dt) =R^2/2 (L/(mR^2)) =L/(2m)`
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