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Figure shows graphs of pressure vs densi...

Figure shows graphs of pressure vs density for an ideal gas at two temperatures `T_(t)` and `T_(2)`

A

`T_1 gt T_2`

B

`T_1 = T_2`

C

`T_1 lt T_2`

D

any of the three is possible

Text Solution

Verified by Experts

The correct Answer is:
A
From the ideal gas equation: `P /rho = (RT)/M`
Hence, the slope of pressure-density graph is proportional to temperature.

From the graph we can see that slope of graph for `T_1` is greater than slope for `T_2`
So `T_1 gt T_2`
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