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A mono-atomic gas is taken along path AB...

A mono-atomic gas is taken along path AB as shown. Calculate change in internal energy of the gas.

A

`279 . 8 J`

B

`341 J`

C

`241 J`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
D
`Delta U = f/2 nR(T_f - T_c) = f/2 (P_f V_f - P_i V_i) = 3/2 (500 xx10-200 xx250 ) xx10^(-3) J = `zero
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