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In a cyclic process shown in the figure ...

In a cyclic process shown in the figure an ideal gas is adiabatically taken from `B`to`A`, the work done on the gas during the process `B`to`A` is `30,J` when the gas is taken from `A` to `B` the heat absorbed by the gas is `20 J` Then change in internal energy of the gas in the process `A` to `B` is :

A

`20 J`

B

`- 30 J`

C

`50 J`

D

`- 10 J`

Text Solution

Verified by Experts

The correct Answer is:
B
Ba, Adiabatic Process
`Delta U = W`
`Delta U = -(-30) `
`Delta u = 30 J`
So in process AB
`Delta U = -30 J`
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