A Carnot refrigerator works between two temperatures of 300 K & 600 K. Find the COP of the refrigerator if heat removed from lower temperature in 300 J.

Options

A. `1`
B. `1.2`
C. `0.5`
D. `0.8`

Explanation

To find the Coefficient of Performance (COP) of a Carnot refrigerator operating between two temperatures, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the temperatures**:
- The temperature of the cold reservoir (T_c) is 300 K.
- The temperature of the hot reservoir (T_h) is 600 K.

2. **Understand the formula for COP of a refrigerator**:
The Coefficient of Performance (COP) for a Carnot refrigerator is given by the formula:
\[ \text{COP} = \frac{T_c}{T_h - T_c} \]
where:
- \( T_c \) is the absolute temperature of the cold reservoir,
- \( T_h \) is the absolute temperature of the hot reservoir.

3. **Substitute the values into the formula**:
- Substitute \( T_c = 300 \, \text{K} \) and \( T_h = 600 \, \text{K} \) into the COP formula:
\[ \text{COP} = \frac{300}{600 - 300} \]

4. **Calculate the denominator**:
- Calculate \( 600 - 300 = 300 \).

5. **Complete the calculation**:
- Now substitute back into the equation:
\[ \text{COP} = \frac{300}{300} = 1 \]

6. **Final result**:
- The Coefficient of Performance (COP) of the refrigerator is 1.