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One mole of a gas is subjected to two pr...

One mole of a gas is subjected to two process AB and BC, one after the other as shown in the figure. BC is represented by `PV^(n) = constant`. We can conclude that (where T = temperature, W = work done by gas, V = volume and U = internal energy).

A

`T_A = T_B = T_C`

B

`V_A lt V_B , P_B le P_C`

C

`V_(AB) lt V_(AB)`

D

`U_A lt U_B`

Text Solution

Verified by Experts

The correct Answer is:
D
AB : Isobaric process
`V prop T`
`rArr T_B =2 T_A`
So `U_B = 2U _A`
` U_B gt U_A`
Or `U_A lt U_B`
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