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A gaseous mixture consists of 16g of hel...

A gaseous mixture consists of 16g of helium and 16 g of oxygen. The ratio `(C_p)/(C_v)` of the mixture is

A

`1.54`

B

`1.62`

C

`1.4`

D

`1.59`

Text Solution

Verified by Experts

The correct Answer is:
B
`n_1=4,n_2=(1)/(2)`
`gamma_1=(3)/(5)` (for monatomic gas)
`gamma_2= (67)/(5)` (for diatomic gas)
`(n_1+n_2)/(gamma-1)= (n_1)/(gamma_1 -1)+(n_2)/(gamma_2 -1) implies (4+0.5)/(gamma-1)= (4)/((5)/(3)-1)+(1"/"2)/((7)/(5)-1)`
`implies (4.5)/(gamma-1)=(12)/(2)+(5)/(4)=(29)/(4) implies (gamma-1)/(4.5)= (4)/(29)`
`implies gamma-1= (4xx.4.5)/(29)=0.62 implies gamma=1.62`.
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