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The work of 146 kJ is performed in order...

The work of 146 kJ is performed in order to compress one kilo mole of a gas adiabatically and in this process the temperature of the gas increases by `7^@C`. The gas is `(R=8.3ml^-1Jmol^-1K^-1)`

A

diatomic

B

triatomic

C

a mixture of monatomic and diatomic

D

monatomic

Text Solution

Verified by Experts

The correct Answer is:
C
As the process is adabatic,
`triangleU = -triangleW = 1.46 xx 10^(5)J " ""……………"(i)`
Also, `triangleU= nc_(v)triangleT=(nf)/(2)RtriangleT= 10^(3)xx (f)/(2)xx 8.3xx 7J" ""……………"(ii)`
From (i) and (ii) we get f=5 (diatomic).
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