Home
Class 12
PHYSICS
The temperature of an open room of volum...

The temperature of an open room of volume `30 m^(3)` increases from `17^(@)C to 27^(@)C` due to sunshine. The atmospheric pressure in the room remains `1 xx 10^(5) Pa`. If `n_(i) and n_(f)` are the number of molecules in the room before and after heating then `n_(f)` and `n_(i)` will be

A

`1. 38 xx10^(23)`

B

`2.5 xx10^(25)`

C

`-2.5 xx10^(25)`

D

`-1.61 xx10^(23)`

Text Solution

Verified by Experts

The correct Answer is:
C
From `pv=nRT-(N)/(N_(A))RT`
We have, `n_f-n_i=(pVN_A)/(RT_f)-(pVN_A)/(RT_i) implies n_f-n_i=(10^5xx 30)/(8.2)xx 6.02xx10^(23)*((1)/(300)-(1)/(290))`
`= -2.5xx10^(25)" ":. Trianglen= -2.5xx10^(25)`.
Promotional Banner

Similar Questions

Explore conceptually related problems

The total number of air molecules in a room of capacity 20 m^(3) at a temperature of 27^(@)C and 1 atm pressure is

One bar is equivalent of 10^(5)N//m^(2) . The atmosphere pressure is 1.0313xx10^(5)N//m^(2) . The same in bar is

Ten moles of N_(2) , contained at constant pressure, is heated from 27^(@)C to 527^(@)C . Calculate the amount of heat required. R - 2 cal /(mol xx .^(@)C ).

The approximate number of air molecules in a 1 m^3 volume at room temperature (300 K) and atmospheric pressure is (Use R = 8.2 xx 10^(-5 ) m^3 atm/mol K and N_A =6.02 xx 10^(23) mol^(-1) )

The kinetic energy of translation per unit volume of the molecules of hydrogen gas at N.T.P. is (Atmospheric pressure = 10%5N//m^2 )

The number of gas molecules striking per second per square meter of the top surface of a table placed in a room at 20^(@)C and 1 atmospheric pressure is of the order of (k_(B) = 1.4 xx10^(-23) J/K, and the average mass of an air molecules is 5xx10^(-27) kg)

What is the pressure inside a drop of mercury of radius 3.0mm at room temperature? Surface tension of mercury at that temperature (20^(@)C) is 4.65xx10^(-1)Nm^(-1) . The atmospheric pressure is 1.01xx10^(5)Pa . Also give the excess pressure inside the drop.

The molecules of a given mass of gas have a rms velocity of 200 m//sec at 127^(@)C and 1.0 xx 10^(5) N//m^(2) pressure. When the temperature is 127^(@)C and pressure is 0.5 xx 10^(5) N//m^(2) the rms velocity in m//sec will be

50 students sitting in the room of 5 xx 10 xx 3m^(3) dimensions. The air inside the room is at 27^(@)C and 1atm pressure. If each student loses 100 watt heat per second assuming the walls, ceiling floor, and all the material present inside the room is perfectly insulated as well as neglecting loss of air to the outside as the temperature is raised, how much rise in temperature will be noticed in 10min ? Given C_(P) = (7)/(2)R for air.