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Following figure shows two process A and...

Following figure shows two process A and B for a gas. If `Delta Q_(A)` and `Delta Q_(B)` are the amount of heat absorbed by the system in two case, and `Delta U_(A)` and `Delta U_(B)` are changes in internal energies, respectively, then :

A

`Delta Q_A gt Delta Q_B, Delta U_A=Delta U_B`

B

`Delta Q_A lt Delta Q_B, Delta Q_A ltDeltaU_B`

C

`Delta Q_A Delta Q_B, Delta U_A = Delta U_B`

D

`Delta Q_A gt Delta Q_B, Delta U_A gtDelta U_B`

Text Solution

Verified by Experts

The correct Answer is:
A
Area under curve process 'A' on P-V diagram is more. Hence
`W_(A) gt W_(B) :. Triangle Q_(A) gt triangleQ_(B) " & "triangleU_(A) = triangleU_(B)`.
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