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The temperature of an ideal gas is incre...

The temperature of an ideal gas is increased from 120 K to 480 K. If at 120 K the root mean square velocity of the gas molecules is v, at 480 K it becomes

A

`4V`

B

`2V`

C

`V//2`

D

`V//4`

Text Solution

Verified by Experts

The correct Answer is:
B
`v_("m s") = sqrt((3RT)/m) " i.e., "v_("m s") prop sqrtT`
When temperature is increased from to (i.e., four times), the root mean square speed will become `sqrt4` or 2 time ie., 2V.
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