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The average translational energy and the...

The average translational energy and the rms speed of molecules in a sample of oxygen gas at `300K` are `6.21xx10^(-21)J` and `484m//s`, respectively. The corresponding values at `600K` are nearly (assuming ideal gas behaviour)

A

`12.42 xx10^(-21)` J,968 m/s

B

`8.78 xx10^(-21)` J,968 m/s

C

`6.21 xx10^(-21)` J,968 m/s

D

`12.42xx10^(-21)` J,968 m/s

Text Solution

Verified by Experts

The correct Answer is:
D

The formula for average kinetic energy is `( bar(KE))= 3/2 KT`
`:." "((bar(KE))_(600K))/((bar(KE))_(300K)) = 600 /300 " "rArr" "(bar(KE))_(600K) = 2xx6.21 xx10^(-21) J = 12.42 xx10^(-21 )J`
Also the formula for rms velocity is `C_("m s") = sqrt((3KT)/m)`
`:." "((C_("m s"))_(600 K))/((C_("m s"))_(300 K))= sqrt(600/300) " "rArr" "(C_("m s"))_(600 K)= sqrt2 xx484 = 684m//s`
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