Home
Class 12
PHYSICS
5.6 liter of helium gas at STP is adiaba...

5.6 liter of helium gas at STP is adiabatically compressed to 0.7 liter. Taking the initial temperature to be `T_1,` the work done in the process is

A

`9/8 RT_1`

B

`3/2 RT_1`

C

`15/B RT_1`

D

`9/2 RT_1`

Text Solution

Verified by Experts

The correct Answer is:
A
Number of moles of He ` = 5.6 //22.4 = 1/4`
Now `T(5.6)^(gamma -1) = T_2 (0.7)^(gamma-1)`
`T_1 = T_2 (1/9)^(2/3) " "rArr r T_1 = T_2`
Work done ` = -(nR[T_2 - T_1])/(gamma -1) =(1)/4(R3T_1)/(2/3) = - 9/8 RT_1`
Promotional Banner

Similar Questions

Explore conceptually related problems

A gas ( gamma =1.5) is enclosed in a container of volume 150 cm^3 . The initial pressure and the initial temperature are 1.5 xx 10^5 Pa and 300K respectively. Of The gas is adiabatically compressed to 50 cm^3 , find the final pressure and temperature and the work done by the gas in the process. Also find the total change in internal energy of the gas in the process.

One mole of an ideal gas (gamma=7//5) is adiabatically compressed so that its temperature rises from 27^(@)C to 35^(@)C the work done by the gas is (R=8.47J/mol-K)

Five moles of neon gas (molecular weight=20) at 2 atm and 27^@C is adiabatically compressed to one-third its initial volume. Find the final pressure, the temperature and the work done on the gas.

The initial temperature of a two mole monoatomic gas is T. If temperature increases to 3T then work done in the adiabatic process is

n moles of a gas are filled in a container at temperature T. If the gas is slowly and isothermally compressed to half its initial volume, the work done by the atmosphere on the gas is

One litre of dry air STP undergoes through an adiabatic process and reaches to a final temperature of 89.6 °C, the work done by air is : [Take air to be an ideal gas and gamma_("air")=1.4 use R =8.3J mol^(-1)K^(-1)]

One mole of gas of specific heat ratio 1.5 being initially at temperature 290 K is adiabatically compressed to increase its pressure 8 times. The temperature of the gas after compression will be

The volume of an ideal gas (gamma 1.5 ) is changed adiabatically from 4.00 liters to 3.00 liters . Find the ratio of (a) the final pressure to the initial pressure and (b) the final temperature to the initial temperature.