Heat given to process is positive. Match the following options of column I with the corresponding options in

Answer

`A-Q; B-P S; C-S, D-Q. R`

Explanation

A–Q, B–P, S, C–S, D–Q, R
In process `J to K : V` is constant whereas p is decreasing. Therefore, T should also decrease.
`W = 0, Delta U = "negative and "Q lt 0`
In process `K to L :P` is constant while V is increasing. Therefore, temperature should also increase.
`W = 0, Delta U gt 0" and "q gt 0`
In process `L to M :` this is inverse of process ` J to K`.
`W = 0, Delta u gt 0" and "Q gt 0`
In process `M to J : V` is decreasing
Therefore `W lt 0`.
`(PV)_J lt (PV)_M" "T_J lt T_M" , "Delta U lt 0`.