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An ideal gas is taken through a cyclic t...

An ideal gas is taken through a cyclic thermodynamic process through four steps. The amounts of heat involved in these steps are `Q_1=5960J, Q_2=-5585J, Q_3=-2980J and Q_4=3645J`, respectively. The corresponding quantities of work involved are `W_1=2200J, W_2=-825J, W_3=-1100J and W_4` respectively.
(1) Find the value of `W_4`.
(2) What is the efficiency of the cycle

Text Solution

Verified by Experts

The correct Answer is:
`10.82`
Efficiency,
`eta = ("Total W rk done in the cycle ")/("Heatabsorbed (positive heat)by the gas during the cycle ")xx100`
`=((W_1 + W_2 + W_3 + W_4)/(Q_1 +Q_4))xx100`
` = {((2200 - 825 - 1100 + 765))/(5960+3645)}xx100`
`=(1040)/(9605) xx100`
`eta = 10.82 %`
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