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A mono-atomic ideal gas of two moles is ...

A mono-atomic ideal gas of two moles is taken through a cyclic process starting from `A` as shwon in the figure below.
The volume ratios are `V_(B)//V_(A) = 2` and `V_(D)//V_(A) = 4`. If the temperature `T_(A)` at `A` is `27^(@)C`. Calculate

a. The temperature of gas at `B`.
b. Heat absorbed or evolved in each process.
c. Total work done in cyclic process.

Text Solution

Verified by Experts

The correct Answer is:
600
Given
Number of moles, n = 2
`C_V = 3/2 R " and " C_P = 5/2 R " (monoatomic)"`
`T_A = 27^@ C = 300 K`
Let `V_A =V_0` then `V_B = 2V_0` and `V_D = V_C = 4V_0`
Process `A to B`
`V prop T rArr T_B /T_A = V_B /V_A`
`:." "(T_B = T)A a(V_B/V_A) = (300)(2) = 600 K`
`:." "T_B = 600K`
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