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A diatomic ideal gas is compressed adiab...

A diatomic ideal gas is compressed adiabatically to 1/32 of its initial volume. If the initial temperature of the gas is `T_i` (in Kelvin) and the final temperature is a `T_i`, the value of a is

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The correct Answer is:
4
`TV^(gamma -1)` = constant
`TV^(7//5-1) =aT (V/32)^(7//5-1) rArr a = 4`
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