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The volume V versus temperature T graphs...

The volume V versus temperature T graphs for a certain amount of a perfect gas at two pressure `p_1 and p_2` are as shown in Fig. It follows from the graphs that `p_1` is greater than `p_2.`

Text Solution

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`"pV = nRT"`
`:." "V = ((nR)/(p))T`
Comparing this with `Y = m x, V - T`. Graph is a straight line passing through origin with slope` = (nR)/P`
or slope `prop 1/p("slope")_1 gt ("slope")_2" ":." "P_1 lt P_2`
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