A simple pendulum of length l and having a bob of mass M is suspended ina car. The car is moving on a circular track of radius R with a uniform speed v. If the pendulum makes small oscillations in a radial direction about its equilibrium, what will be its time period ?

Explanation

The bob of the simple pendulum will experience the acceleration due to gravity and the centripetal acceleration provided by the circular motion of the car.
Acceleration due to gravity = g
Centripetal acceleration =`(v^(2))/(R)` Where,
v is the uniform speed of the car
R is the radius of the track
Effective acceleration`(a_(eff))` is given as `a_(eff)=sqrt(g^(2)+((v^(2))/(R))^(2))`
`T=2pisqrt((I)/(a_(eff)))`
Time period, Where, // is the length of the pendulum `therefore` Time period, `T=2pisqrt((I)/((g^(2)+(v^(2))/(R^(2)))1//2))`.