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The maximum speed of a particle in SHM i...

The maximum speed of a particle in SHM is given by `mA=V_(m)`. The average speed of the particle in terms of maximum speed is given by

A

`(v_(max))/(2)`

B

`((v_(max)))/(pi)`

C

`(piv_(max))/(2)`

D

`(2v_(max))/(pi)`

Text Solution

Verified by Experts

The correct Answer is:
B

Average speed =`(distance)/(time)=(4A)/(T)` (in one cycle)
`v_(max)=Aw=A(2pi)/(T)` `implies (A)/(T)=(v_max)/(2pi)` `therfore v_(avg)=4((v_(max))/(2pi))=(2V_(max))/(pi)`
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