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Frequency of a particle executing SHM is...

Frequency of a particle executing SHM is 10 Hz. The particle is suspended from a vertical spring. At the highest point of its oscillation the spring is unstretched. Maximum speed of the particle is (g=10m/`s^(2)`

A

`2pim//s`

B

`pim//s`

C

`(1)/(pi)m//s`

D

`(1)/(2pi)m//s`

Text Solution

Verified by Experts

The correct Answer is:
D
Amplitude=elongation in equilibrum position.
`A=(mg)/(k)` `V_(max)=Aomega=Aomega=(mg)/(K)omega=(g)/(omega)=(g)/(2pif)=(g)/(2pixx10)=(1)(2pi)m//s(omega=sqrt((K)/(M)))`
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