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Two masses M and m are suspended togethe...

Two masses M and m are suspended together by massless spring of force constant -k. When the masses are in equilibrium, M is removed without disturbing the system. The amplitude of oscillations.

A

`Mg//k`

B

`mg//k`

C

`((M+m)g)/(k)`

D

`((M-m)g)/(k)`

Text Solution

Verified by Experts

The correct Answer is:
A
For equilibrium of (M+n), `x_(1)=((M+m)g)/(k)`
For equilibrium of m `x_(2)=(mg)/(k)`, Amplitude=shift in equilibrium positioin =`(Mg)/(K)`
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