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A spring of spring constant k is cut int...

A spring of spring constant k is cut into n equal parts, out of which r parts are placed in parallel and connected with mass M as shown in figure. The time period of oscillatory motion of mass M is:

A

`T=2pisqrt((M)/(rnK))`

B

`T=2pisqrt((nrM)/(K))`

C

`T=2pisqrt((nM)/(nK))`

D

`T=2pisqrt((nM)/(rK))`

Text Solution

Verified by Experts

The correct Answer is:
A
`K.I=k'xx(I)/(n)` constant
new spring constand for each part is k'=nK
Now r part are taken in parallel.
so `K_(eq)=nrk`, Time period =`2pisqrt((M)/(K_(eq)))=2pisqrt((M)/(nrK))`
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