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A pendulum suspended from the ceiling of...

A pendulum suspended from the ceiling of the train has a time period of two seconds when the train is at rest, then the time period of the pendulum, if the train accelerates 10 `m//s^(2)` will be `(g=10m//s^(2))`

A

increase

B

decrease

C

remain unaffected

D

become infinite

Text Solution

Verified by Experts

The correct Answer is:
B
`t=2pisqrt((L)/((T//m)))`
`T=sqrt((ma)^2)+(mg)^(2)` `Rightarrow ~(T)/(m)=sqrt(a_(0)^(2)+g^(2))`
`t=2pisqrt((I)/((g^(2)+a_(0)^(2)^(1//2)))`
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