Home
Class 12
PHYSICS
A pendulum with time period of 1s is los...

A pendulum with time period of `1s` is losing energy due to damping. At time its energy is `45 J`. If after completing `15` oscillations, its energy has become `15 J`. Its damping constant (in `s^(-1)`) is :-

A

`1/30In3`

B

`1/15In3`

C

2

D

`1/2`

Text Solution

Verified by Experts

The correct Answer is:
A
Amplitude of damped oscillation is `A=A_(0)e^(-bt)`, where b is the damping constant.
Energy, `E=(1)/(2)KA^(2) Rightarrow E=((1)/(2)KA_(0)^(2))E^(-2bt)`
`15=45e^(-2b(1xx15)) Rightarrow 3=e^(30b) Rightarrow b=(1)/(30)`In 3
Promotional Banner

Similar Questions

Explore conceptually related problems

An oscillating pendulum stops, because its energy

If the length of a simple pendulum is halved, then its energy becomes

The time period of oscillations of a simple pendulum is 1 minute. If its length is increased b 44% then its new time period of oscillation will be

The time period of a simple pendulum is 2s. It its length is increased by 4 times, then its period becomes

If a body starts rotating from rest due to a torque of 1.5 Nm, then its kinetic energy after it complete 20 revolution will be

A simple pendulum of length 1 m, and energy 0.2 J, oscillates with an amplitude 4 cm. When its length is doubled then the energy of oscillation will be

The time period of an oscillating simple pendulum is 1s when its amplitude of vibration is 4cm . Its time period when its amplitude is 6cm is

A simple pendulum has time period T. A uniform rod, whose length is the same as that of the pendulum, undergoes small oscillations about its upper end. Its time period of oscillation will be -