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A body of mass 36 g moves with S.H.M. of...

A body of mass 36 g moves with S.H.M. of amplitude A = 13 cm and time period T = 12 s. At time t = 0, the displacement x is + 13 cm. The shortest time of passage from x = + 6.5 cm to x = - 6.5 cm is

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The correct Answer is:
4
x=6.5cm =`(A)/(2)`(`because A=13cm`)
At t=0, `x=13cosomegat` will indicate the S.H.M.
Time taken to move from 13cm to 6.5 cm is
6.6 = 13cos `(omegat)`
`Rightarrow cosomegat=(1)/(2) Rightarrow omegat =(pi)/(3)Rightarrow t=(T)/(6)`
so time taken for x=+6.5cm will be
`2(T)/(6)=(T)/(3)=4sec`
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