Home
Class 12
PHYSICS
A body is executing S.H.M. when its disp...

A body is executing S.H.M. when its displacement from the mean position is 4 cm and 5 cm, the corresponding velocity of the body is 10 cm/sec and 8 cm/sec. Then the time period of the body is

A

`2pi sec`

B

`pi//2sec`

C

`pi sec`

D

`3pi//2 sec`

Text Solution

Verified by Experts

The correct Answer is:
C

`v=omegasqrt(A^(2)-x^(2)) Rightarrow 10=omegasqrt(A^(2)-4^(2))`
`Rightarrow 8=omegasqrt(A^(2)-5^(2)) Rightarrow ((10)/(8))^(2)=(A^(2)-4^(2))/(A^(2)-5^(2)) Rightarrow (25)/(16)=(A^(2)-16)/(A^(2)-25)`
`25A^(2)-625=16a^(2)-256 Rightarrow 9A^(2)=625-256=369 Rightarrow A^(2)=(369)/(9)` `omega=(8)/(sqrt((369)/(9))-25)=(8xx3)/(sqrt369-225)=(8xx3)(12)=2 Rightarrow T=(2pi)/(omega)=pis`.
Promotional Banner

Similar Questions

Explore conceptually related problems

The velocities of a body executing S.H.M. are 3 cm/s and 4 cm/s when the displacements from the mean position are 4 cm and 3 cm, then the period of oscillation is

A body executing S.H.M . has its velocity 10cm//s and 7 cm//s when its displacement from the mean positions are 3 cm and 4 cm respectively. Calculate the length of the path.

The time period of a body executing S.H.M. is 0.05 s and the amplitude of vibration is 4 cm. What is the maximum velocity of the body ?

A body executes SHM has its velocity 10cm//s and 7cm//s when its displacements from mean positions are 3cm and 4cm respectively. The length of path is nearly

The force on a body executing SHM is 4 N when the displacement from mean position is 2 cm. If amplitude of oscillation is 10 cm, then the maximum kinetic energy associated with the SHM will be

A particle executing SHM has a velocity of 2 ms^(-1) when its displacement from mean position is 1 cm and a velocity of 1 ms^(-1) when its displacement is 2 cm. Its amplitude of oscillationis

A partical executes SHM on a straigh line path. The amplitude of oscillation is 2cm. When the displacement of the particle from the mean position is 1cm, the magnitude of its acceleration is equal to that of its velocity. Find the time period of SHM, also the ms. velocity and ms. acceleration of SHM.

The maximum displacement of a particle executing S.H.M. is 1 cm and the maximum acceleration is (1.57)^(2) cm per sec^(2) . Then the time period is

A body is executing SHM . If the force acting on the body is 6N when the displacement is 2cm , then the force acting on the body at a displacement of 3cm is