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The length of a simple pendulum executin...

The length of a simple pendulum executing simple harmonic motion is increased by `21%`. The percentage increase in the time period of the pendulum of increased length is

A

0.11

B

0.21

C

0.42

D

0.1

Text Solution

Verified by Experts

The correct Answer is:
D
`T=2pisqrt((1)/(g))` and T '= `2pisqrt((1.21)/(g))`
`(T)/(T)` '= `sqrt(1.21) implies T'=1.1T implies Delta=0.1T`
Percentage increase in time period is `(DeltaT)/(T)xx100=(0.1T)/(T)xx100=10%`
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