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If a spring of stiffness 'k' is cut into...

If a spring of stiffness `'k'` is cut into two parts `'A'` and `'B'` of length `l_(A):l_(B)=2:3`, then the stiffness of spring `'A'` is given by

A

`5/2k`

B

`3k/5`

C

`2k/5`

D

k

Text Solution

Verified by Experts

The correct Answer is:
A
As F=-kx
`kalpha 1/x alpha 1/1`
for spring , `kalpha 1/1` `therefore k_(A)/k=l/(l_(A)) impliesk_(A)=(l_(A)+l_(B))/(l_(A))k=5/2k`
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