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A pendulum is executing simple harmoni...

A pendulum is executing simple harmonic motion and its maximum kinetic energy is `K_(1)`. If the length of the pendulum is doubled and it perfoms simple harmonuc motion with the same amplitude as in the first case, its maximum kinetic energy is `K_(2)` Then:

A

`k_(2)=2k_(1)`

B

`k_(2)=k_(1)`

C

`k_(2)=k_(1)/4`

D

`k_(2)=k_(1)/4`

Text Solution

Verified by Experts

The correct Answer is:
D
`KE_(max)=1/2momega^(2)A^(2)`
or `(k_(1))/(k_(2))= (g//l)/(g//2l) or k_(2)=k_(1)/2`
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