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A particle undergoing simle harmonic mot...

A particle undergoing simle harmonic motion has time dependent displacement given by `x(t)=Asin (pi t)/(90)`.The ratio of kinetic to potential energy of this partle at t= 210s will be :

A

`1/9`

B

2

C

1

D

3

Text Solution

Verified by Experts

The correct Answer is:
None
`KE=1/2A^(2)omega^(2)cos^(2)(omegatau)`, `PE=1/2A^(2)omega^(2)sin(2)(omegatau)`
So,`R=KE/PE=cotau^(2)(omegatau)=cotau^(2)((pi)/(20)xx210)=1/3`
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