Equation of a progressive wave is given by, `y=4sin[pi((t)/(5)-(x)/(9))+(pi)/(6)]` where x and y are in metre. Then :

Options

A. `v=1m//s`
B. `lamda=18m`
C. `A=0.04m`
D. `f=50Hz`

Answer

B

Explanation

`K=(pi)/(9)=(2pi)/(lamda) implies lamda=18m,omega=(pi)/(5)=2pif implies f=0.1Hz" "C=flamda=1.8m//s`.