A string of mass 0.2 kg/m and length l= 0.6 m is fixed at both ends and streteched such that it has a tension of 80 N. the string vibrates in 3 segments with maximum amplitude of 0.5 cm. the maximum transevers velcotiy amplitude is

Options

A. 1.57 m/s
B. 6.28 m/s
C. 3.14 m/s
D. 9.42 m/s

Answer

A

Explanation

`l=(3lamda)/(2),v=sqrt((T)/(mu)),f=(v)/(lamda),v_(max)=(A_(max))omega=A_(max)(2pisqrt(T//mu))/((2l//3))=(0.5xx2pisqrt(80//0.2))/((2xx(0.6)/(3)))=1.57m//s`