For a certain organ pipe three successive resonance frequencies are observed at 425Hz, 595 Hz and 765Hz respectively. If the speed of sound air is 340m/s, then the length of the pipe is

Options

A. 2.0m
B. 0.4m
C. 1.0m
D. 0.2m

Answer

C

Explanation

Frequencies are in ratio 5:7:9. hence it's closed pipe
Using, `425Hz=5((v)/(4l)) " "l=(5v)/(4xx425)`