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A string is stretched between fixed poin...

A string is stretched between fixed points separated by `75.0cm`. It is observed to have resonant frequencies of `420 Hz` and `315 Hz`. There are no other resonant frequencies between these two. Then, the lowest resonant frequency for this string is

A

105Hz

B

1.05Hz

C

1050Hz

D

10.5Hz

Text Solution

Verified by Experts

The correct Answer is:
A
`nv_(0)= 315 Hz`
`(n+1)v_(0) = 420 Hz rArr v_(0) = 105 Hz`
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