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A travelling wave represented by y=Asi...

A travelling wave represented by
`y=Asin (omegat-kx)`
is superimposed on another wave represented by
`y=Asin(omegat+kx).` The resultant is

A

a stainding having nodes at `x=(n+(1)/(2))(lamda)/(2),n=0,1,2`

B

a wave travelling along +x direction

C

a wave travelling along -x direction

D

a standing wave having nodes at `x=(nlamda)/(2),n=0,1,2`

Text Solution

Verified by Experts

The correct Answer is:
A

By superposition principle,
`y=y_(1)+y_(2)= A sin(omegat - kx)+ A sin(omegat + kx)y=2 A sin omega t cos kx`
Clearly, it is equation of standing wave for position of nodes y=0.
i.e., `x=(2n+1)(lambda)/(4) rArr (n+(1)/(2))(lambda)/(2), n = 0,1,2,3`
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