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An observer is moving with half the spee...

An observer is moving with half the speed of light towards a stationary microwave source emitting waves at frequency 10 GhHz. What is the frequency of the microwave measured by the observer? (speed of light=`3xx10^(8)ms`)

A

12.1GHz

B

17.3GHz

C

15.3GHz

D

10.1GHz

Text Solution

Verified by Experts

The correct Answer is:
B

As the observer is moving towards the source, so frequency of waves emitted by the source will be given by the formula
`f_(observed)=f_(actual^(.))((1+V//C)/(1-V//C))^(1//2)`
Here, `f_(observed) = f_(actual) ((3//2)/(1//2))^(1//2)` `therefore` `f_(observed) = 10xxsqrt(3)=17.3 GHz`
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