Equation of travelling wave on a stertched string of linear density `5 g // m` is y=00.3 sin (450 t - 9 x) where distance and time are measured in SI units. The tension in the string is

Options

A. 12.5N
B. 7.5N
C. 10N
D. 5N

Answer

A

Explanation

`V = (omega)/(K)=(450)/(9)=50m//S` `V=sqrt(T)/(mu)`
So, `T = muV^(2) = 5xx10^(-3) xx 2500 = 12.5 N`