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A stationary source emits the sound of f...

A stationary source emits the sound of frequency `f_0 = 492` Hz. The sound is reflected by a large car approaching the source with a speed of `2 ms^(-1)`. The reflected signal is received by the source and superposed with the original. What will be the beat frequency of the resulting signal in Hz? (Given that the speed of sound in air is `330 ms^(-1)` and the car reflects the sound at the frequency it has received).

Text Solution

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The correct Answer is:
6

Frequency recived by car `=[(330+2)/(330-2)]xx496 square 495 Hz`
Frequency received by source `=330/(330-2)xx495 square 498 Hz`
Original frequency `f_1=492 Hz`
Beat frequency `=|f_1-f_2|=6 Hz`
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