Sound waves of frequency `660 Hz` fall normally on a perfectly reflecting wall. The shortest distance from the wall at which the air particles have maximum amplitude of vibration is ……………… meters.

Answer

0.125

Explanation

`C=vlambda therefore lambda=c/v=330/660=0.5m`
The antinode will be at a distance of `lambda/4=0.5/4=0.125m`