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The velocity –position graph of a partic...

The velocity –position graph of a particle moving along a straight line is shown. Then acceleration of the particle at s = 15 m is :

A

` (2)/(3) ms^(-2) `

B

` -(2)/(3) ms^(-2) `

C

` (20)/(3)ms^(-2)`

D

` -(20)/( 3)ms^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
D
` V(s) =20 -(2s)/(3) rArr (15)=10 m//s(dv)/(ds) =` slope of v-s graph ` =-(2)/(3)`
`a(S) =(dv)/(ds) =(v) =((dv)/(ds)) =(10 ) ((-2)/(3)) =(-20 )/(3) m//s^(2) `
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